The query below returns tables in a database with the space they use, sorted by those that use more.
select schema_name(tab.schema_id) + '.' + tab.name as [table], cast(sum(spc.used_pages * 8) / 1024.00 as numeric(36, 2)) as used_mb, cast(sum(spc.total_pages * 8) / 1024.00 as numeric(36, 2)) as allocated_mb from sys.tables tab inner join sys.indexes ind on tab.object_id = ind.object_id inner join sys.partitions part on ind.object_id = part.object_id and ind.index_id = part.index_id inner join sys.allocation_units spc on part.partition_id = spc.container_id group by schema_name(tab.schema_id) + '.' + tab.name order by sum(spc.used_pages) desc
Tables in the AdventureWorksLT database, sorted from the ones that use more space to the ones that use less.